Darrenz
Darrenz Darrenz
  • 04-08-2018
  • Mathematics
contestada

ANSWER CORRECTLY AND I WILL PUT YOU THE BRAINLIEST!
(SEE ATTACHMENT BELOW)

ANSWER CORRECTLY AND I WILL PUT YOU THE BRAINLIEST SEE ATTACHMENT BELOW class=

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mathmate
mathmate mathmate
  • 05-08-2018

the inverse of a two-by-two matrix

A=[tex] \left[\begin{array}{ccc}a&b\\c&d\end{array}\right] [/tex]

whose inverse is

[tex]A^{-1}=\frac{\left[\begin{array}{ccc}d&-b\\-c&a\end{array}\right]}{ad-bc}[/tex]

Substituting values, we get

[tex]A^{-1}=\frac{\left[\begin{array}{ccc}7&9\\-8&-5\end{array}\right]}{37}[/tex]

which is not the same as matrix B. Therefore B is not the inverse of A.

We can prove similarly that A is not the inverse of B.

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