ccj2609 ccj2609
  • 01-09-2019
  • Mathematics
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cos²x - 2 sin²x = -2 .Help me to solve it ​

Respuesta :

kosala1478
kosala1478 kosala1478
  • 01-09-2019

Step-by-step explanation:

note that

sin²x = (1-cos²x)

LHS= cos²x - 2 sin²x

= cos²x - 2(1-cos²x)

= cos²x - 2 + 2cos²x

= 3cos²x - 2

or

cos²x = (1-sin²x)

LHS= cos²x - 2 sin²x

=1-sin²x - 2 sin²x

= 1-3sin²x

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