Answer:
80 mL
Explanation:
M= mol solute/ L solution
mol solute= M * L solution
mol solute = (0.200 M * 0.4 L)
mol solute = 0.08 mol NaOH= mol OH
We need the same amount of H mol to neutralize
L solution= mol solute/M
L solution= 0.08 mol HCl/ 1.00M
L solution= 0.08 L= 80 mL
