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  • 04-06-2020
  • Mathematics
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Given ΔADC and ΔAEB, What is AE?

Given ΔADC and ΔAEB What is AE class=

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ronhagrid310
ronhagrid310 ronhagrid310
  • 04-06-2020

Answer:

As shown in picture,

EB is perpendicular with AC

DC is perpendicular with AC

=> EB // DC

Applying Thales theorem:

BC/AC = ED/AD

=> AD = ED x AC/BC = 72 x 88/55 = 115.2

=> AE = AD - ED = 115.2 - 72 = 43.2

Hope this helps!

:)

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