Answer:
[tex]\boxed{\sf QS = 98}[/tex]
Step-by-step explanation:
QP = PS [Diagonals are bisected(Divided into two equal parts) by the other diagonal of parallelogram]
So,
3x - 11 = 2x + 9
3x - 2x = 9 + 11
x = 20
Now,
QS = QP + PS
QS = 3x-11+2x+9
QS = 3(20)-11+2(20)+9
QS = 60 - 11 + 40 + 9
QS = 49 + 49
QS = 98
