Complete Question:
Suppose George wins 34β% of all chess games. β
(a) What is the probability that George wins two chess games in aβ row?
β(b) What is the probability that George wins three chess games in aβ row? β
(c) When events areβ independent, their complements are independent as well. Use this result to determine the probability that George wins three chess games in aβ row, but does not win four in a row.
Answer:
(a) [tex]Probability = 0.1156[/tex]
(b) [tex]Probability = 0.0393[/tex]
(c) [tex]Probability = 0.0259[/tex]
Step-by-step explanation:
Represent Win with W
So, we have:
[tex]W = 34\%[/tex]
Solving (a): Winning two in a row;
This is represented by WW and is calculated as thus:
[tex]Probability = W * W[/tex]
[tex]Probability = 34\% * 34\%[/tex]
[tex]Probability = 0.1156[/tex]
Solving (b): Winning three in a row;
This is represented by WWW and is calculated as thus:
[tex]Probability = W * W * W[/tex]
[tex]Probability = 34\% * 34\% * 34\%[/tex]
[tex]Probability = 0.039304[/tex]
[tex]Probability = 0.0393[/tex] (Approximated)
Solving (c): Wins three in a row but lost the fourth
Represent Losing with L
L is calculated as:
[tex]L = 1 - W[/tex] ---- Complement of probability
[tex]L = 1 - 34\%[/tex]
[tex]L = 66\%[/tex]
This probability is represented by WWWL and is calculated as thus:
[tex]Probability = 34\% *34\% *34\% *66\%[/tex]
[tex]Probability = 0.02594064[/tex]
[tex]Probability = 0.0259[/tex] (Approximated)