chasenkcastro chasenkcastro
  • 01-12-2020
  • Mathematics
contestada

This assignment is hard as heck lol!

This assignment is hard as heck lol class=

Respuesta :

jimrgrant1 jimrgrant1
  • 01-12-2020

Answer:

z = 3[tex]\sqrt{13}[/tex]

Step-by-step explanation:

Using the altitude- on- hypotenuse theorem

( leg of large Δ )² = ( part of hypotenuse below it ) × ( whole hypotenuse )

z² = 9 × (9 + 4) = 9 × 13 = 117 ( take square root of both sides )

z = [tex]\sqrt{117}[/tex]

  = [tex]\sqrt{9(13)}[/tex]

  = [tex]\sqrt{9}[/tex] × [tex]\sqrt{13}[/tex]

  = 3[tex]\sqrt{13}[/tex]

Answer Link

Otras preguntas

what are the differences between german and english schools
Jim has a box in the shape of a rectangular prism. The area of the base of the box is 48 square inches. The volume of the box is 144 cubic inches. let h= the he
need help with this question#20
How many times dose 150 go into 1000
what is the density of a orange if its mass is 158.2 g and the volume is 106 mL
A definition for cyber bullying
What energy is transfomed that takes place you lifting a chair?
need help with this question#20
What is the velocity of an object that has a mass of 2.5 kilogram and a momentum of 1,000 kg·m/sec?
Two numbers have a product of 48 and a sum of 19 what are the numbers and how do you know