Respuesta :

shaha75

2xy^2+xy^2+xy-2x

2x(y^2-1)+xy(y+1)

2x(y-1)(y+1)+xy(y+1)

(y+1)(2xy-2x+xy)

(y+1)(3xy-2x)

  • I divide 3xy^2 into 2xy^2+xy^2

3xy² + xy - 2x

  • Take x common from all the terms.

= x (3y² + y - 2)

  • Now, split the middle term of the bracketed portion.

= x (3y² + 3y - 2y - 2)

= x {3y (y + 1) - 2 (y + 1)}

= x (y + 1) (3y - 2)

Answer:

[tex]x (y + 1) (3y - 2)[/tex]

Hope you could understand.

If you have any query , feel free to ask.

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