Respuesta :

Answer:

(c) neither odd nor Even

Step-by-step explanation: ​

f(x) odd ⇒ f(-x) = - f(x)

⇒ g(-x) = f(-x) + 2  = - f(x) + 2

Since - f(x) + 2 ≠ - f(x) - 2  and   - f(x) + 2 ≠  f(x) + 2

Then     g(-x) ≠ - g(x)         and   g(-x) ≠ g(x)

Then g is neither  odd      nor    even