mineyobeezwack360
mineyobeezwack360 mineyobeezwack360
  • 14-06-2022
  • Mathematics
contestada

HEEEEEEEEEELPPPPPPPPPPPPPP ASAAAAAAAAAAAAAAAPPPPPPPP

HEEEEEEEEEELPPPPPPPPPPPPPP ASAAAAAAAAAAAAAAAPPPPPPPP class=

Respuesta :

loneguy
loneguy loneguy
  • 14-06-2022

Answer:

[tex]C)~3x^3 y[/tex]

Step-by-step explanation:

[tex]~~\sqrt[3]{27x^9 y^3}\\\\=\left(27 x^9 y^3 \right)^{\tfrac 13}\\\\=\left(3^3 x^9 y^3\right)^{\tfrac 13}\\\\=3x^3y[/tex]

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