The factors are 1 , -1 twice and 3
Here, we want to find the rational roots of;
[tex]f(x)\text{= }x^4-2x^3-4x^2+2x+3[/tex]We can start here by trying out simple numbers if we cannot factorize the polynomial at a go
The given polynomial here can be factorized
We can express it as;
[tex]x^4-2x^3-4x^2+2x+3\text{ = (}x-1)(x+1)^2(x-3)[/tex]So what we have here is to simply equate individual linear factor to zero
Thus, we have the factors as;
1 , -1 twice and 3
