rockem rockem
  • 01-04-2017
  • Mathematics
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Help help help help help

Help help help help help class=

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Аноним Аноним
  • 01-04-2017
it is the second one x≠6 solution is extraneous

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bcalle
bcalle bcalle
  • 01-04-2017
It's the first one.
(2sqrt(x-5))=2
Divide both sides by 2
sqrt(x-5) = 1
Square both sides
x -5 = 1^2
x-5 = 1
Add 5 to both sides
x = 6
CHECK
2sqrt(6-5) =
2sqrt(1)=
2*1=
2
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