Respuesta :
The generic equation of the line is:
 y-yo = m (x-xo)
 Where,
 m = (y2-y1) / (x2-x1)
 m = (1-6) / (- 6-6)
 m = (- 5) / (- 12)
 m = 5/12
 We choose an ordered pair:
 (xo, yo) = (6, 6)
 Substituting values:
 y-6 = (5/12) (x-6)
 y = (5/12) x - 2.5 + 6
 y = (5/12) x + 3.5
 y = (5/12) x + 7/2
 Answer:
 the equation of the line is:
 y = (5/12) x + 7/2
 y-yo = m (x-xo)
 Where,
 m = (y2-y1) / (x2-x1)
 m = (1-6) / (- 6-6)
 m = (- 5) / (- 12)
 m = 5/12
 We choose an ordered pair:
 (xo, yo) = (6, 6)
 Substituting values:
 y-6 = (5/12) (x-6)
 y = (5/12) x - 2.5 + 6
 y = (5/12) x + 3.5
 y = (5/12) x + 7/2
 Answer:
 the equation of the line is:
 y = (5/12) x + 7/2
Using two-point slope form;
 y-yo = m (x-xo)
 m = (y2-y1) / (x2-x1) m = (1-6) / (- 6-6) m = 5/12
y-yo = 5/12 (x-xo)
use (6,6) as(xo,yo)
 y-6 = (5/12) (x-6)
 y = (5/12) x + 7/2
 y-yo = m (x-xo)
 m = (y2-y1) / (x2-x1) m = (1-6) / (- 6-6) m = 5/12
y-yo = 5/12 (x-xo)
use (6,6) as(xo,yo)
 y-6 = (5/12) (x-6)
 y = (5/12) x + 7/2